Reetika Hooda Dominates in Paris: Quarterfinals Beckon

Indian wrestler Reetika Hooda advanced to the quarterfinals of the women's 76 kg freestyle event at the Paris Olympics. She outclassed Bernadett Nagy of Hungary with a 12-2 lead, forcing the referee to stop the match in the second round. Reetika will face top-seed Aiperi Medet Kyzy next.

Indian wrestler Reetika Hooda showcased an impressive blend of power and skill to enter the quarter-final of the women's 76 kg freestyle event at the Paris Olympics. Reetika outclassed Hungary's Bernadett Nagy, forcing the referee to call off the match in the second round with 29 seconds remaining, as the Indian grappler gained a commanding 10-point lead to secure a 12-2 victory.

Reetika established her dominance early on, leading 4-0 in the first round with a leg-hold maneuver followed by a flip. Despite a brief comeback from Nagy, Reetika was unstoppable in the second round, racking up multiple two-point scores to seal her place in the next stage.

Later today, Reetika will face a tough challenge against top-seed Aiperi Medet Kyzy of Kyrgyzstan in the quarterfinals, with high stakes on the line for the Indian wrestler.

(With inputs from agencies.)